Question

\begin{align*} & 2a-\dfrac {1} {2a+3}=3\\ & \left( 2a+3\right) ^{2}+\dfrac {1} {\left( 2a+3\right) ^{2}}=?\end{align*}

Answer 1

İlk ifadeye 3 eklersek ve $2a+3=k$ dersek.

$k^2+\frac{1}{k^2}-2=36$ ve $k^2+\frac{1}{k^2}+2=t^2$ ise $t=?$