Question

$\displaystyle\int \dfrac {1} {x^{2}-x-6}dx$ integralini bulunuz.

Answer 1

$\dfrac{1}{x^2-x-6} =\dfrac{1}{(x-3).(x+2)}=  \dfrac{1}{5(x-3)} -  \dfrac{1}{5(x+2)}$

$\displaystyle\int (\dfrac{1}{5(x-3)} -  \dfrac{1}{5(x+2)})dx$

$=\dfrac{1}{5}(ln|x-3|-ln|x+2|)+c$