Question

$\begin{align*} & x=0,481\\ & y=2,519\end{align*} $ old. göre $\left( \dfrac {3x} {y}+\dfrac {3y} {x}+6\right) .xy$ ifadesinin değer nedir ?

Comments

( x+y ) him karesinen faydalan

Answer 1

$ ( \frac {3x} {y}+ \frac {3y} {x}+6) .xy$

=$3( \frac {x^2y} {y}+ \frac {xy^2} {x}+2xy) $

=$3(x+y)^2$

=$ 3(0,481+2,519)^2=3.3^2=27 $