Question

$\sqrt [6] {4-2\sqrt {3}}.\sqrt [3] {1+\sqrt {3}}=?$

Answer 1

$\sqrt[6]{(\sqrt 3-1)^2}.\sqrt[3]{1+\sqrt3}=\sqrt[3]{\sqrt 3-1}.\sqrt[3]{1+\sqrt3}=\sqrt[3]{(\sqrt 3-1)(1+\sqrt3)}=\sqrt[3]{2}$