x−2 parantezine alabilirsin.
(x−1).(x+1).(x−2)=(x−2).(x+2).(x−3)(x−1).(x+1).(x−2)−(x−2).(x+2).(x−3)=0(x−2).[(x−1).(x+1)−(x+2).(x−3)]=0(x−2).[x2−1−x2+x+6]=0(x−2).(x+5)=0x1=2 ve x2=−5Ç.K = (-5 , 2 )