$\dfrac{dy}{dx}=\dfrac{2y}{e^x}$ ise
$\dfrac{dy}{2y}=\dfrac{dx}{e^x}$ integral alalım,
$\displaystyle\int \dfrac{dy}{2y}=\displaystyle\int\dfrac{dx}{e^x}$
$\dfrac{\ln y}{2}=-e^{-x}+C$
$y=e^{(-2e^{-x}+C)}$
$y(0)=1=e^{(-2+C)}$
$C=2$
$y=e^{(-2e^{-x}+2)}$
$y(-ln2)=e^{-2}$ gelir.