Question

$f(x)=(x-30)(x-31)....(x-51)$   çarpımı verlidiğine göre,

$f(40)+f'(50)$ toplamı ?

Answer 1

Merhaba

f(40)=0   , turev kismi icin (x-50 )1.carpan geei kalan digerleri de 2.carpan olsun.

f(x)=(x-50).[(x-51).(x-49).(x-48)...(x-30)]

f'(x)=[(x-51).(x-49).(x-48)...(x-30)]+(x-50).[x-51).(x-49).(x-48)...(x-30)]'

f'(50)-=1.1.2.3...20+0=-20!

Cevap da buna gore -20!

Kolay gelsin

Comments

sağolun hocam :))