$(\frac{2^{-7}+2^{-4}+2^{-3}}{2^{-6}-2^{-6}+2^{-5}})^\frac{-1}{2}=(\frac{2^{-6}-2^{-6}+2^{-5}} {2^{-7}+2^{-4}+2^{-3}})^\frac{1}{2}$ olur ve içerdekilerden hepsini $2^{-7}$ parantezine alırsak,
$\left(\frac{2^{-7}(\underbrace{\underbrace{2-2}_0+2^{2}}_4)} {2^{-7}(\underbrace{1+2^{3}+2^{4}}_{25})}\right)^\frac{1}{2}$ buradaki $2^{-7}$ ler sadeleşir ve,
$=\left(\dfrac{4}{25}\right)^{\frac{1}{2}}$ kalır. bu da ,
$\dfrac{2}{5}$ demektir.
$\boxed{\left(\frac{2^{-7}+2^{-4}+2^{-3}}{2^{-6}-2^{-6}+2^{-5}}\right)^\frac{-1}{2}=\dfrac{2}{5}}$