Question

$F(x)= \int_0^{x^2}\frac{dx}{\sqrt{ 1+x^4 }}$ $F'(1)$'i bul

Answer 1

İpucu:

$$F(x)=\int_{\alpha(x)}^{\beta(x)}f(t)dt\Rightarrow F'(x)=f(\beta(x)).\beta'(x)- f(\alpha(x)).\alpha'(x)$$