Question

$\left( 1+i\right) .\left( 1-i\right) ^{5}=-a+b+ai+bi$

$z=a+bi$

$\overline {z}$ ?

Answer 1

 ifadeyi düzenlersek

$\underbrace{[(1-i)(1+i)]}_{2}.\underbrace{(1-i)^4}_{(-2i)^2=-4}=(-a+b)+i.(a+b)$


$-8=(-a+b)+i.(a+b)$   solda i li ifade olmadıgından


$a+b=0\quad \longrightarrow \quad a=-b$


$\underbrace{-a}_b+b=-8=2b$

$b=-4 \quad a=4$

Comments

eyvallah atom,erkencisin :F

---

:D